# How to write one-step equations for word problems | 6th grade | Khan Academy | Summary and Q&A

137.8K views
September 11, 2015
by
How to write one-step equations for word problems | 6th grade | Khan Academy

## TL;DR

The content explains how to write equations to determine the number of boxes of pizza or candy that can be bought based on the total amount spent or the fundraising goal.

## Install to Summarize YouTube Videos and Get Transcripts

### Q: How can you determine the number of boxes of pizza Anna can buy with a total of \$42.50?

To find the number of boxes, divide the total amount (\$42.50) by the price per box (\$8.50), resulting in the equation p = 8.5 x 42.5.

### Q: How can the equation in the first example be rearranged to find the price per box instead of the number of boxes?

To find the price per box, divide both sides of the equation p = 8.5 x 42.5 by 42.5, yielding 8.5 = 42.5/p.

### Q: How can you calculate the number of boxes of candy Mr. Herman's class needs to sell to reach their \$500 goal?

Divide the fundraising goal (\$500) by the amount made per box (\$2.75) to obtain the equation 2.75c = 500, where c represents the number of candy boxes.

### Q: How does the equation for the second example differ from the equation in the first example?

While the structure is similar, the second equation (2.75c = 500) represents the fundraising goal as the total amount made (2.75 per box times c boxes) and is set equal to the target amount of \$500.

## Summary & Key Takeaways

• The first example involves Anna and her friends wanting to buy pizza. By dividing the total amount spent on pizza by the price per box, the equation p = 8.5 x 42.5 is derived.

• The second example features Mr. Herman's class selling candy for a school fundraiser. By dividing the fundraising goal of \$500 by the amount made per box (\$2.75), the equation 2.75c = 500 is formed.