# Limit of (1 - e^(3x^2))/(xsin(2x)) as x approaches 0 | Summary and Q&A

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September 23, 2022
by
The Math Sorcerer
Limit of (1 - e^(3x^2))/(xsin(2x)) as x approaches 0

## TL;DR

This video explains how to evaluate a limit using L'Hopital's Rule when the limit is in an indeterminate form.

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### Q: What is the indeterminate form mentioned in the video, and why is it important?

The indeterminate form discussed is 0/0, which means that both the numerator and denominator approach zero. It is important because it indicates that further evaluation is needed to find the limit.

### Q: How does L'Hopital's Rule help in evaluating the limit?

L'Hopital's Rule states that for an indeterminate form, taking the derivatives of the numerator and denominator can simplify the expression and potentially provide a determinate form that can be easily evaluated.

### Q: What are the steps involved in applying L'Hopital's Rule?

The steps include taking the derivative of the numerator, derivative of the denominator, simplifying the expression, and checking if the resulting expression still has an indeterminate form. If it does, the process is repeated until a determinate form is obtained.

### Q: Why is it necessary to check if the resulting expression still has an indeterminate form after applying L'Hopital's Rule?

It is essential to ensure that the process of taking derivatives does not result in another indeterminate form. If it does, repeating the application of L'Hopital's Rule is necessary to find the limit accurately.

## Summary & Key Takeaways

• The video demonstrates how to evaluate the limit as x approaches 0 of a complicated expression involving exponentials, trigonometric functions, and variables.

• The first step is to plug in the value of x and check if it results in an indeterminate form.

• If an indeterminate form such as 0/0 or infinity/infinity is obtained, L'Hopital's Rule is used to find the limit by taking derivatives of the numerator and denominator successively.