you don't want to see this on your calculus test (calculus 1 limit)  Summary and Q&A
TL;DR
Computing the limit of a function as T approaches 0 using algebraic manipulations and the conjugate method.
Questions & Answers
Q: What is the purpose of finding a common denominator when subtracting fractions?
Finding a common denominator allows us to combine the fractions into a single expression and simplify the algebraic manipulations.
Q: How does multiplying the numerator and denominator with the conjugate help in computing the limit?
Multiplying the numerator and denominator with the conjugate helps to eliminate the square root in the numerator and simplify the expression for further calculations.
Q: Why is the limit considered an indeterminate form when plugging in 0 for all the T's?
Plugging in 0 for all the T's results in an indeterminate form (0/0), which means additional algebraic manipulations are required to find the actual limit value.
Q: How are the square roots and squares simplified in the expression?
The square roots and squares are simplified by canceling out each other, resulting in a simplified expression without any radicals or squares.
Summary & Key Takeaways

The video explains the process of computing the limit of a function as T approaches 0 by manipulating algebraic expressions.

Common denominators are obtained to combine fractions, and the limit is simplified by multiplying the numerator and denominator with the conjugate.

The final result of the limit calculation is 1/2.